RallyeRedSi
Member
- :
- 2008 Civic Si
though 130 ft lbs torque at the wheels doesn't(dance)
(smash)
though 130 ft lbs torque at the wheels doesn't(dance)
Why do you have such a hard-on about torque? It has nothing to do with acceleration. Acceleration is completely dependent on (wheel) hp. Dumping on other peoples cars was cool back in high school.
Unless car people abuse the vocabulary, I can say as a physics teacher that torque on a wheel will affect acceleration greatly.
Why do you have such a hard-on about torque? It has nothing to do with acceleration. Acceleration is completely dependent on (wheel) hp.
Carroll Shelby said:Horsepower sells cars, torque wins races.
Why do you have such a hard-on about torque? It has nothing to do with acceleration. Acceleration is completely dependent on (wheel) hp.
Dumping on other peoples cars was cool back in high school.
Whilst this is way off topic....
You're a little confused... engine torque may not have a great deal to do with acceleration, but WHEEL TORQUE (that is *geared* torque) most certainly does.
If you multiply out the torque you are producing at a given RPM, by the gear ratio (including final drive and wheel diameter), you can work out the force (torque) being delivered to the wheels. This force (less rolling resistance, friction, the effect of weight and air resistance) is directly related to how fast you accelerate.
Where people get it HORRIBLY wrong is thinking that LOW END torque is important... the truth is the later you can produce your peak torque, the quicker you will go because of gearing. This is why cars with high peak HORSEPOWER (torque and horsepower are very much related) accelerate much faster than cars with a very high, but very early peak torque, assuming weight is the same. The high horsepower car produces a far greater amount of WHEEL TORQUE at higher RPM.
I've got all the graphs and so forth laying around here if you are interested in learning more - send me a pm....
Sorry for derailing the thread.... carry on...
Capt Crunch said:OK dudes and dudettes, it's time to finally set Torque vs. Horsepower to rest. Not to blow my own horn, but I have a Math and Physics degree so I'm not a complete idiot. Most of this is my own work, but I did get some examples and wording from a little research on the internet.
Part 1 - Introduction
"OMG my car pushes me back in the seat, it's got mad torque y000000!!!11"
Wrong, your car has mad horsepower y00000000.
Part 2 - The MATH
The math isn't that hard, even if you're lazy I encourage you to read this part.
Let:
F = Force
M = Mass
A = Acceleration
P = Power (motive)
V = Velocity
T = Torque
So we've all seen F = MA before. Standard physics and says for a fixed mass, force is proportional to acceleration. The people that have a hard-on about torque say: "Well, torque is a force, so the higher peak torque I have, the faster my car will go!" This is wrong, torque is not the force described here. We need to go a little bit further.
At a instant in time motive power (P) is:
P = FV
Rearranging gives F = P/V
Plugging this in to F = MA gives P/V = MA which in turn gives:
A = P/(MV)
Acceleration = Power / (Mass x Velocity)
This equation is the real deal. In this case acceleration is proportional to power which is measured in units of, you guessed it, horsepower.
Part 3 - WTF WHAT ABOUT TORQUE YOU FOOL?!!1
First let me start with Carroll Shelby's famous quote: "Horsepower sells cars, torque wins races." While I have the utmost respect for Shelby, this statement is misleading at best and at worst betrays massive ignorance about physics. It's wrong. Don't listen to it. Listen to me.
Torque is a force applied to a moment arm. One foot-pound of torque is taking a 1-foot socket wrench and pushing with 1 lb of force on the end of the wrench. The way an engine produces torque is the engine makes and explosion and pushes the piston down which in turn applies a torque on the crankshaft.
Where does horsepower come in? We first let's assume that an engine produces the same torque, say X ft-lbs, at any rpm. If you look at a dynograph this would be manifested by a flat torque line. The LS1-7 motors make a very nice flat torque line.
So lets floor our imaginary engine at 1000 rpm. The pistons turn the crank with the torque of X ft-lbs. Now let's floor our engine at 4000 rpm. The pistons are still turning the crank with the same torque, X ft-lbs, but this time it's applying it 4 times faster. How does this difference manifest itself?
Power = Torque / Time
What this equation implies is that power is proportional to torque and inversely proportional to time. This means if you double the torque, the power is doubled. Conversely, if you half the time taken, the power doubles. So the equation with units included is:
Power (horsepower) = [ Torque (ft/lbs) x RPM (revolutions/minute) ] / 5252 (revolutions)
HP = [ Torque x RPM ] / 5252
The 5252 is just a constant. Notice the revolution units cancel and you get units of (ft/lbs)/minute, which is exactly as above. Thus for our ideal engine if you spin at 4000 RPM instead of 1000 RPM you are applying the same torque in a quarter of the time, which means you are quadrupling your horsepower.
Part 4 - So why does my high-torque car feel faster?
Because it's making more horsepower. At a given RPM, if you increase the torque you increase the power and thus the acceleration. It's not that torque is something unrelated to horsepower and makes you faster all by itself.
Part 5 - Why more hp = fastAr in werds
You may have noticed from the equation A = P/(MV) that if you double the power you double the acceleration. "But Crunch," you ask, "If I double my RPM then I double my power, which means I double my acceleration, but I never feel it!" Correct, you don't, but that's because if you double your RPM then you are doubling your speed. Then you get:
A = 2P/(M * 2V) = P/(MV)
Which is exactly what you had before. The doubling of the speed cancels out whatever increase in power you make as a result of increasing the RPM. In other words, for a SPECIFIC GEAR (you cannot compare differently geared cars) P/V= Torque * rpm/V = Torque * C where C is a constant related to the gear ratio. So you get:
A = Torque * C/M
Or in other words, constant torque implies constant acceleration.
Don't let this equation fool you. This equation does not take gearing into account, change the gearing and you change the constant C. Let's see what happens when we compare differently geared cars. So lets look at out ideal motor which makes the same torque at all RPM. One engine with torque of 400 ft-lbs redlines at 4k, the other with 200 ft-lbs redlines at 8k. Plugging these into our little equation, both cars make the same peak HP. The first, 304.6 hp at 4k RPM, the second 304.6 hp at 8k RPM. If the cars are geared in such a way that both cars are going the same speed at their redline (4k and 8k respectively), then these cars will be equally fast. Why?
Well for the first car:
A_1 = torque * C/M
but for the second car the torque is halved, but the gear ratio constant is doubled.
A_2 = .5 * torque * 2 * C/M = A_1
The accelerations are the same!
Another way to think about it is looking at the dyno graph. Sometimes dyno graphs have horsepower listed as a function of speed. This takes gearing out of the equation and is easier to understand. Lets say you dyno the two cars above so that for each dyno run they go from 0 rpm to redline, which for both cars equates to, say, 120 mph. Then, their graphs will look identical. It will be a straight line from 0 hp at 0 RPM to 304.6 hp at 120 mph. They will be as fast as each other in EVERY SINGLE SITUATION EVER and yet one makes double the torque of the other.
So whoever has the most area under the HORSEPOWER curve over the rev range used will be faster. If you're racing and you shift from 6-8k RPM, the only thing that matters is how much power you're making from 6-8k RPM. If you're making 500 whp from 6-8k RPM and 5 whp everywhere else and your buddy is making 400 whp from 4-6k but has 5x the peak torque as you, you have nothing to worry about.
NO IF, ANDS, OR BUTS, HORSEPOWER WINS RACES. FORGET TORQUE AT THE ENGINE. NOTHING ABOUT IT IS IMPORTANT OTHER THAN IT MAKES HORSEPOWER.
Q.E.D.
What you're saying is exactly my point. People rail about how a Civic has no torque, but they're referring to torque at the engine. Put in the gear multipliers and a 200 hp civic makes as much torque at the wheels as a 200 hp GTI.
Here's a very long but simple explanation that I wrote for everyone else that swears by the Carol Shelby quote:
I did not read all the way through to see how we got from voided warranty to torque discussions..?
I think the low end torque on the MS3 (or any car) is a real positive for everyday driveability. You only need to use a few gears in city driving and always have decent power on tap. Having this power at lower RPM's means a quieter engine and less vibration for normal everyday driving.
So I contend that low end torque IS important, but only for driveability reasons. My sport bike is at the other end of the spectrum, making most of its power high in the RPM band (8K-11K). This is great for acceleration, but means a lot of shifting and a much higher RPM to keep decent power on tap. Naturally the higher RPM's = more noise and vibration.
If you roll over and take that your doing exactly what they hope. I doubt a throttle sensor failed because of boost controller, bpv and gauge. Figh them legally you have nothing to lose.
Read the owners manual, any mods will void the warranty.
Not true, the Moss-Magnuson Act specifically prohibits voiding a warranty based merely on the installation of aftermarket parts. Mazda has 100% of the burden to prove with a preponderance of the evidence that the aftermarket parts(s) caused the failure for warranty coverage is sought...
Read the owners manual, any mods will void the warranty.
Not true, the Moss-Magnuson Act specifically prohibits voiding a warranty based merely on the installation of aftermarket parts. Mazda has 100% of the burden to prove with a preponderance of the evidence that the aftermarket parts(s) caused the failure for warranty coverage is sought...
Aye. Fed law trumps any owner's manual.
Read the owners manual, any mods will void the warranty.
Not true, the Moss-Magnuson Act specifically prohibits voiding a warranty based merely on the installation of aftermarket parts. Mazda has 100% of the burden to prove with a preponderance of the evidence that the aftermarket parts(s) caused the failure for warranty coverage is sought...
In theory, but not in practice. I've said this a million times. You bring car in. Dealer voids warranty. You cite Moss-Magnuson. Dealer says to go pound sand. You come on to the forums crying because you don't have money for a lawyer and you don't have another daily driver.
In theory, but not in practice. I've said this a million times. You bring car in. Dealer voids warranty. You cite Moss-Magnuson. Dealer says to go pound sand. You come on to the forums crying because you don't have money for a lawyer and you don't have another daily driver.
The you file in Magistrate-Small Claims court with no lawyer...Mazda still has the burden of proof to prove the aftermarket part caused the failure. In you do nothing you lose...so why not at least try?
I'd like to hear of one case where a warranty was voided for aftermarket parts (especially a boost controller and/or voltage clamp) and gone to court and mazda paid! Seriously this is totally unrealistic!
Cars are getting more and more hard to modify without causing other problems with everything being controlled by the ecu!
My warranty was out the window at under 8k miles but I knew that going into it.
The you file in Magistrate-Small Claims court with no lawyer...Mazda still has the burden of proof to prove the aftermarket part caused the failure. In you do nothing you lose...so why not at least try?