stock fuel pressure of 36 at zero boost, then:
Needed fuel pressure = ( PR2 x 36) + boost = (1.412 x 36) + 6 = 77.5 psi
Well, fuel flow through the injectors is a function of the SQUARE ROOT of the fuel pressure change. Basically,
F2/F1 = sqrt(P2/P1)
Here, F2/F1 is "new flow over old flow" which is your PR of 1.41. P2 is the new, desired pressure, and P1 is the stock pressure. Rearranging the equation gives,
1.41 = sqrt(P2/P1)
(1.41)^2 = P2/P1
1.99 = P2/P1
1.99 * P1 = P2
1.99 * 57psi = P2
therefore, P2 = 113psi
ok it's simple, 0 is the angle at which combustion begins; it is about equal to the angle of spark firing. the angle of the duration of combustionis -0. the constants A&M are determined experimentally. real burn fraction curves have been fitted by the Weibe funtion with A=5 and M=2
the terms in equation (2) can be arranged to give an expression for pressure in terms of the crank angle and the conditions at the onset and end of combustion. the final conditions can be represented as funtions of the initial conditions by using the fact that the gases in the cylinder act almost ideal and that negligible is lost or gained by the system.since the combustion process occurs almost symmetrically about top center (TC), the volume of the cylinder at the spark is approximately equal to the volume at the end of compustion. because the initial and final volumesare about equal, little net work is done on the piston and the change in temperaturebetween the spark and end of combustion is due to the burning of the fuel. hope that helps!