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| (sin 2x)^5(cos 2x)dx
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| (sin 2x)^4(cos 2x)(sin 2x)dx
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mp3moose said:I just failed a calc exam yesterday. Praying is your best option.
this guy knows what he's talkin about. if i need to do integrals, i love my ti-89DaleGribble said:You're on the right track. If you let u=sin(2x), then it's derivative, du=2cos(2x). Then your original integral becomes:
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2| u^5 du
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because you can pull constants out of integrals.
So that looks like a form that's familiar.
Then your solution to that is 2*(1/6)u^6 = (1/12)u^6
Then you resub with u=sin(2x) to get your final answer as
(1/12)(sin(2x))^6...I think
DaleGribble said:You're on the right track. If you let u=sin(2x), then it's derivative, du=2cos(2x). Then your original integral becomes:
/
2| u^5 du
/
because you can pull constants out of integrals.
So that looks like a form that's familiar.
Then your solution to that is 2*(1/6)u^6 = (1/12)u^6
Then you resub with u=sin(2x) to get your final answer as
(1/12)(sin(2x))^6...I think