I specifically said I used 100 hp. The exact quote was, "I had to use 100 hp, a 1.6 liter displacement and a VE of 0.75 to get an engine weak enough." I used 100 hp in both methods, the Garrett method (which you stated worked and staked your position on while lambasting my understanding of it earlier), and the "rule of thumb." The goal power in both was 400 hp. So, the answer is indeed correct, only your understanding of the methods is "wrong."
Anyone who remembers one iota of high school chemistry and algebra (you know, math that is proven to work) would likely remember the Ideal Gas Law. A simple little equation that reads, "PV=nRT." Air isn't an ideal gas, but at the relatively low levels of change we're dealing with, we can ASSUME it behaves as one for simplification.
Now, the average high school algebra student can probably tell you that when you're changing one side of the equation, something on the other side has to change as well to maintain equality. Math that works, right?
In this case, we'll change the P (pressure) while leaving the V (volume, in this case displacement) constant. On the other side we'll leave the T (Temperature) constant as well, though in real life that will change and, once again, is the efficiency of the system. The R (Gas Constant) also remains the same since we're just talking about plain ol' air and not replacing it with some exotic substance. And that leaves us with what?
Here is the answer - it leaves us with the ratio of the change in pressure being equal to ratio of the change in number of moles of the gas. Since the number of moles directly relates to the mass, and the change in mass is what produces a change in power, what we end up with is, "Doubling the absolute pressure doubles the power." "Tripling the absolute pressure triples the power." Math that is proven to work?
It's that simple. And by the way, that's EXACTLY What the Garret mathematics are saying, except that they're running the necessary airmass through the equation as well.
And since a naturally aspirated motor makes it's power at an absolute pressure of 14.7 psia at STP, it stands to reason that every time you multiply that, you can multiply the power by the same amount. The rule of thumb.
And it required all that arguing to say, 'A stock MS3 motor cannot make 465+ rwhp at 20 psi.' A nicely screwed together combo could, but not a stock setup. The stock parts could be strong enough, but they're just not efficient enough, just like someone said earlier.
