getting burnt out

[Dexter]

ive been sittin inside all day working on my calc homework, and its just one hurdle after another. i can do the problems from the book fine, but then the problems on the practice test **** me in the ass. blah, ive got a test tommorow and a quiz tuesday and a final thursday. up mine. **** you. up yours.

this server is slow as dicks too, what the ****?

 

[Captain KRM P5]

as much as i hate work, i hate school more.

 

[mazdaspeedpower]

I noticed the server's been slow again too...what up with that?

And calc homework sucks majour balls...I know.

 

[Mr. Win]

you have a weakness???

























im with ken though... school blows.

 

[DE31]

just another week of school for me. then i get my actual vacation for 2 weeks then back to school.

 

[KonspiracyImage]

sucks to be you!

 

[Lord_Zath]

I always had the same problem w/calc. Thought I was doing good and understood everything until the test. Then I was proven incorrect.

Good luck Bryan. Don't get frustrated, I'm sure you'll do just fine.

 

[anarchistchiken]

**** calc man. I hate math more than I hate the rest of school.

 

[Captain KRM P5]

wait - they have schools in Alabama ?

 

[fLyPiNoY7]

im with u on calc...it is such a pain in the ass...i have a midterm on wednesday, the 2nd of 3 tests which account for 90% of my grade...first one i got a 53% on it...so if i fail this one, i pretty much dont have a chance of passing this class...

 

[Dexter]

just another week of school for me. then i get my actual vacation for 2 weeks then back to school.

yup, same.

 

[DE31]

i just look to the bright side. a movie on the last day since we have nothing else to do then six flags to celebrate.

yup, same.

 

[Dexter]

wow. i get to work full time for celebration.

 

[DE31]

lucky.

 

[SpicyMchaggis]

two things bryan.

(1) Come to fullsail and quit bitching, even RISM is here now

(2) Konspiracy, you have the worst sig ever. Rice.

 

[Dexter]

i have to calculate the cost for this box, alright

its got a square base
Dexter750: (x by x)
Dexter750: and height h
Dexter750: material for the sides costs 3 dollars sq/ft
Dexter750: and for the base is 5 dollars sqft
Dexter750: also, there is no top
Dexter750: so its cost of base + cost of 4 sides, right?
Dexter750: 5(x^2)+4(3(xh))
Dexter750: makes sense, right
Dexter750: volume is fixed at 20 cubic feet
Dexter750: so V=x^2h
Dexter750: consequently 20 = x^2h
Dexter750: to get the h out of the cost function, solve the volume one for h
Dexter750: 20/x^2 = h
Dexter750: plug that back into the cost one, right, and you've got all x's

12(x(20/x^2) + 5(x^2) = Cost of the Crackrock storage box
^ did i get that correctly?

The company that mfgs these containers has determined it can afford a cost of at most 160 per container. What dimensions for the container produce a cost of at most 160. Explain the procedure you used to solve this problem.

solving that b**** of a cost equation for 160 doesnt work...because no x will ever make it equal exactly 160 (i been playing with an excel sheet i made and my graphing calculator...it wont even solve for x.....so what the fux to me)...

 

[siberiankiss]

was the volume fixed at 20 cubic feet given to you?

 

[Lord_Zath]

i have to calculate the cost for this box, alright

its got a square base
Dexter750: (x by x)
Dexter750: and height h
Dexter750: material for the sides costs 3 dollars sq/ft
Dexter750: and for the base is 5 dollars sqft
Dexter750: also, there is no top
Dexter750: so its cost of base + cost of 4 sides, right?
Dexter750: 5(x^2)+4(3(xh))
Dexter750: makes sense, right
Dexter750: volume is fixed at 20 cubic feet
Dexter750: so V=x^2h
Dexter750: consequently 20 = x^2h
Dexter750: to get the h out of the cost function, solve the volume one for h
Dexter750: 20/x^2 = h
Dexter750: plug that back into the cost one, right, and you've got all x's

12(x(20/x^2) + 5(x^2) = Cost of the Crackrock storage box
^ did i get that correctly?

The company that mfgs these containers has determined it can afford a cost of at most 160 per container. What dimensions for the container produce a cost of at most 160. Explain the procedure you used to solve this problem.

solving that b**** of a cost equation for 160 doesnt work...because no x will ever make it equal exactly 160 (i been playing with an excel sheet i made and my graphing calculator...it wont even solve for x.....so what the fux to me)...

if you have a box, you have 4 sides and 2 bases, right? So wouldn't it be 2(5(x^2)) + 4(3(xh))?

I'll look at it more when I get some timez

 

[goku4658]

if you have a box, you have 4 sides and 2 bases, right? So wouldn't it be 2(5(x^2)) + 4(3(xh))?

I'll look at it more when I get some timez

yeah but he says that the box comes topless! whoo!

 

[simmadown]

Dude screw calc, i had a class last semester called Circuits theory. Hardest class ever. I answered 41 points out of 150 on the final exam. And they gave me a raw score of 50! and a weighted score of 50% when all was said and done. i passed the class and then promptly changed my major!