Battery current leakage

Hello everyone. I have a 2020 Mazda CX-5, I decided to measure the current leakage in the battery break with the GSM security system "Prizrak 8 gl" in security mode. As it turned out, the car falls asleep for about 12 minutes before setting an average value of 40-60 mA and short-term current surges up to 110 mA. Which discharges a new 61 Ah battery from 12.7 to 12.5 volts overnight. I'm interested in what the values are on similar cars. Since I want to find out if my leak is too big?
 

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  • С прошивкой 4.28.mp4
    33.8 MB
50mA * 12V = 600mW = 0.6W
Not much. Much less than a tiny light bulb.
With your security system, this is expected.

Your 12V battery showing 12.5v is within normal range.
A full/heathy 12V should measure 12.6v (2.1v * 6 cells).
Anywhere between 12.4 to 12.6v is normal.
 
I always try to have my little jump pack aboard. I think this kind of minor leakage must be pretty common. I know if I wait a week the battery will be low, I don't know if I should try waiting two weeks:(
A lot of people get those NOCO Genius battery maintainers.
 
I always try to have my little jump pack aboard. I think this kind of minor leakage must be pretty common. I know if I wait a week the battery will be low, I don't know if I should try waiting two weeks:(
A lot of people get those NOCO Genius battery maintainers.
To be on the safe side, I have a jump starter in my car. It is also useful to help others.
Don't forget to charge the jump starter regularly (every two months).

Suppose you need at least 20% capacity to start the engine.
80% of 60Ah = 48Ah
48Ah divided by 50mA = 40 days
 
Let's assume that with a minimum voltage of 12.0 volts, the car engine can start. I made a calculation in which my car can stand in the parking lot if it is not disturbed. According to various Internet sources, a rechargeable battery with a voltage of 12.7 volts has 100% capacity, and if there is a voltage drop due to a current leak to 12.0 volts, it will have a residual charge capacity of approximately 20%. In my case, with a 61 AH battery. and with a current leakage of 60 mA with a security system, the calculation will look like this: 20% of the remaining battery charge capacity corresponds to a residual capacity of 12.2 A.h.. Next, divide 12.2 by 0.06A and get an approximate time of 203 hours or 8 days 11 hours, at which the car is able to stand in guard mode, which after this time, a successful start of the car engine is possible.

111.webp
 
When using your data:
You start with full capacity = 100%.
When you end with 20% you have used 80% of the battery capacity due to the parasitic current.
The time to use this 80% of your battery capacity is 80% times 61Ah divided by 60mA is almost 34 days.

My CX-5 started without any hesitation after being parked for 4 weeks while I was abroad.
 
Thank you for paying attention to this, you are right, I admit my mistake, I was in a hurry. 61 Ah 80% will be 48.8 Ah, which is about 33.8 days, which is very good.
 

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